Apartments for Rent in New Albany, Indiana
More than just an apartment complex. We are a community.
Finding an apartment complex in New Albany, Indiana that fits your needs can be tough. Some apartment buildings may have all the amenities that you need but the price is out of your budget. Others may be affordable but do not fit the needs of you or your family. Kingsfield Apartments is the solution when you are searching for an apartment to rent in Southern Indiana.
Kingsfield Apartment complex is tucked away off of Green Valley Rd. in New Albany. Our facility boast a quiet country setting in the heart of a bustling city. Minutes away from the IUS Campus, and blocks away from dining, leisure and work, our apartment buildings are the perfect place to call home.
Luxury Apartments in New Albany
Rent an apartment that has all the features you need and want. Whether you are a single individual or looking to start your family, Kingsfield Apartment complex is the luxury place to live at an affordable price.Contact Us
- Kendra LaMure
- Jennifer Shenk
- Katie Martin
Apartment Complex in New Albany, Indiana
Luxury Apartments at Affordable Prices
The Kingsfield Apartment complex is made up of 13 apartment buildings. The amount of area that our complex and apartment buildings cover gives our renters their own exclusive and quiet place to live. Our complex is set back away from busy roads. No worrying about unwanted traffic driving by at high speeds. The only people driving by are your neighbors and their visitors.
Our large apartment complex also increases safety for renters. By limiting unwanted traffic from traveling around the apartment buildings, it reduces the risk of incidents. Giving you and your family a secure place to live and play is the goal of the Kingfield Apartment team. When you want the best apartments in New Albany, rent at Kingsfield Apartments. Talk with our leasing staff today to setup a tour of our apartment complex.
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Have any questions about renting an apartment at Kingsfield? Send us an email and we will answer any questions.